QUADRATIC FUNCTIONS | Solving Quadratic Inequalities (Page 2 of 2) |
We now interpret the inequality in terms of the function we have graphed. The solution set will be all values of x for which the function Y1 has positive or zero y-values. Let's use TRACE to identify where these values of x are. Since the x-intercepts have a y-value of 0, they are part of the solution set. The x-values to the left of -1.83 yield positive y-values, as well as the x-values to the right of 3.83. The inequality means that the graph of Y1 (the parabola) must lie on or above the x-axis. Looking at the graph, we observe this is true if x is to the left of -1.83 or to the right of 3.83. So, the solution set is approximately , or in interval notation, . |
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